A man bought a Pig for $60,
Then, he sells it for $70.
He buys it back for $80, but sells it again for $90
How much money did he make?
Message Board Archives
Lets see how smart you are
In reply to openning
Zero.
In reply to maj
Wrong answer
Mathematically $20
In reply to Kay
This quiz is from Facebook, Caribbean Cultural Vibrations, you should see the answers.
In reply to openning
10 bucks?
In reply to maj
Wrong answer
In reply to openning
Damn it..20 bucks..
If we ignore the bag ($5 for that! ) he sold it in:
Total expenditure = $60 + $80 = $140
Total income = $70 + $90 = $160
Profit = income - expenditure
Profit = $160 - $140
Profit = $20
In reply to openning
He bought it for 60, sells for 70 = gain of 10
Buys it back for 80, put him at -10
10 dollars added to original purchase price minus profit
90 minus 70 = 20
I know, it's fuzzy math.
In reply to black
True. He is now 10 in the black.
No, he is now 70 in the red (- 80 + 10 = -70).
He ends up with 20 in the black. (-70 + 90 = 20)
Moral of the story: Don't change your handle from "black" to "red".
In reply to Norm
You are correct, I was just about to change it.
$20- transaction costs and taxes.
In reply to openning
Then, he sells it for $70.
He buys it back for $80, but sells it again for $90
How much money did he make?
How long does he keep that pig in between buy-sale, I would think he would lose money because he has to pay for feed.
If I buy a 10 lb pig and feed it till it reaches 50lb, selling it for a $10 more is no profit!!
This is the ultra pragmatic answer
In reply to openning
He did 2 separate transactions with the hog, each time profiting $10 each. So, yeah, his total profit is $20.
In reply to steveo
but you are assuming he held it for a while, that is not stated there!
why not assume arbitrage?
20
A number of smart cookies on this mb.
For though who still not understanding the math, this video will help you
Link Text
Shoite! I tort it was just $10! Fact! I taught 6th grade math for 7years in NYC! I feel really bad...gwine give my 12yo boy when he comes home this PM!
three fiddy
In reply to steveo
Market value bro, it is a good thing you fed that pig
In reply to Norm
Lots of ways to do the math...Here is one that leaves no doubt...
As it is just one pig then I would look at it this way..
$60 to invest. $60 invested out of pocket.
From that $60, a sale made with an appreciation of $10 = $70 now available to invest.
Invest that $70 + an additional $10 to buy back in = $70 now invested out of pocket.
$90 final sale price out of $70 out of pocket investment = $20 profit
Just regular Math
-60+70-80+90
=20
In reply to ray
Wrong...This is you reading what has been posted then doing the math according to how you understand it...He does not buy in for 60 and 70 or sell for 80 and 90 so as a practical matter that is wrong.
In reply to Ayenmol
Please...kerr yuh skont..20 is correct
In reply to ray
20 is correct...But the idea is to show your work as to how it is 20 and the math representation you supplied does not harmonize with the problem given.
Our math teacher use to ask us to show our work...ie show how you came to the answer based on the problem given...Your math does not display the math problem described...and your response shows that as well.
If you say he bought at 60 and 80 and sold at 70 and 90...then your math leads to an even break.
If you say he bought at 60 sold at 70 he made $10. Then the spent that $10made to buy in at $80 then sold at $90 then you would arrive...practically at $10 profit.
You gotta show the reasoning to where the deliniation exist.
In reply to Ayenmol
should be
that is a cash flow presentation.
In reply to camos
you mean (60+70)-(80+90)?
Still does not show his work...
That is an easy way to represent it after knowing the answer...but 60 is a purchase price and 70 is a sale price, same for the latter equation...so why are you adding sale price and purchase price?
In reply to camos
If you are trying to represent the problem given in this manner it would be...
(-60+70)+(-80+90)=20
In reply to Ayenmol
ok...np
In reply to ray
Of course that still omits the other factor, that after making $10 from the first equation $10 was lost repurchasing the item for $80. Which as far as i can see would return the equation to a $10 profit.
So the best way to come to the right answer, in my mind, with the burden of displaying your work would be the way I did initially!
In reply to Ayenmol
The man bought twice ,and sold twice. On each occasion he made a profit of $10 .You cannot lose on a purchase ,you can only lose on a sale. Even though it cost him $10 extra on the second purchase it doesnt mean he lost $10 .It simply means he had to find $10 more in order to carried out the transaction,he got his 80 back plus $10 profit .
Total cost of purchase 60 +80 =140
Total sale 70+90 =160
profit = sale -purchase 160 -140
In reply to ray
In reply to cricketmad
In cash flow analysis(-) indicates an out flow of cash and (+ )indicates cash received, you sum them for the result, works every time!
In reply to cricketmad
As a practical matter, what if he had to borrow the additional $10 to make that repurchase?
Point taken though...
In reply to Ayenmol
That would have made no difference.
In reply to cricketmad
Yeah you right. I over thought it there for a moment.
In reply to Chrissy
lol lol
Once a man twice a child, I guess.
Here's a tea & water one fuh alyuh: two prime numbers whose total is 400!? Be honest & tell mih how long it took ya!
Four students live in the same apartment house. Find the age of each student and on which floor they live.
1. Tony, Susan, Oliver and Rosa each live on a different floor of a four-story apartment house.
2. Their ages are 14, 13, 12 and 10, but not necessarily in that order.
3. Tony lives directly above the thirteen-year-old and directly below the twelve-year-old.
4. Susan has to pass by the ten-year-old to leave the building from her apartment.
5. Susan is more than one floor away from Rosa, who is more than one year younger than Susan.
In reply to BeatDball
First off, you may not be totally useless after all.
I believe they are 173 and 227.
Start with 400/2 = 200, and work backward. Highest integer prime factor would be square root of 200 = 13. This is needed to limit check for a prime number.
First pair of candidates: 199 + 201.
201 is a multiple of 3.
Fail.
Next pair: 197 + 203.
197 is not a multiple of 2, 3, 5, 7, 11 or 13. Prime number.
203 is not a multiple of 2, 3, or 5, but is a multiple of 7.
Fail.
Next pair: 193 + 207.
207 is a multiple of 3.
Fail.
Next pair: 191 + 209.
191: Not multiple of 2, 3, 5, 7, 11 , 13. Prime.
209: Not multiple of 2, 3, 5, 7, but is a multiple of 11.
Fail.
Next pair: 187 + 213.
213 is a multiple of 3.
Fail.
Next pair: 181 + 219.
219 is a multiple of 3.
Fail.
Next pair: 179 + 221.
179: Not multiple of 2, 3, 5, 7, 11 or 13. Prime.
221: Not multiple of 2, 3, 5, 7, or 11, but is a multiple of 13.
Fail.
Next pair: 173 + 227.
173: Not multiple of 2, 3, 5, 7, 11 or 13. Prime.
227: Not multiple of 2, 3, 5, 7, 11 or 13. Prime.
Pass.
Took about 25 minutes.
In reply to BeatDball
Rosa is 10 and lives on the 1st (lowest) floor.
Oliver is 13 and lives on the 2nd floor.
Tony is 14 and lives on the 3rd floor.
Susan is 12 and lives on the 4th (highest) floor.
Tony lives directly above the thirteen-year-old and directly below the twelve-year-old.
1. Tony is either 10 or 14 years old.
2. Tony lives on the 2nd or 3rd floor.
1. Susan is 12, 13 or 14 years old.
2. The 10-yr-old lives on the 1st floor.
1. Rosa is 10 or 12 years old.
At this point, the problem reduces to 2 guesses: Rosa is 10, or Rosa is 12.
Assume Rosa is 10. Thus,
1. Rosa lives on the 1st floor.
2. Tony is 14 years old.
3. Susan is 12 or 13 years old.
4. Susan lives on the 3rd or 4th floor (more than one floor from Rosa).
5. Tony, who lives on the 2nd or 3rd floor, cannot live above Susan.
6. Tony lives directly below Susan. Thus Susan is 12 years old, and lives on the 4th floor.
The rest is simple.
Normy! U are a badjohn. But, why work with multiples...do the opposite & work with composite numbers (more than 2 factors)! Remember, not all odd numbers are prime numbers, right? So, immediately figure if the odd number is a composite number!! Anyway, I had 3 and 397!
Max respect for doing the other perfectly! Did you diagram it? Sometimes, it helps. My 12yo boy was getting 'wrapped around the axle' with, more than & the idea of atleast! Anyway, more in the future.
In reply to BeatDball
Because prime numbers have no factors, except 1 and and themselves. Thus, 297 could be divider by 3 without remainder, and is therefore not a prime number. Thus, 3 and 297 cannot be a solution.
In any case, 3 + 297 = 300, not 400. You probably meant 3 + 397. There may also be other solutions.
No, I used the text only.
Brave youngster! Tackling stuff that big men in the Back Room all ran from. Please don't tell him who you hang out with. He might want a divorce right away!
Still, a lot depends on the current math idiom that they are pushing in school.
Alright! Make them a bit easier tho. Start with something like "How many long hops does Bishoo have to bowl before taking a wicket?", for example. We need more participation. These Back Room folks head hard bad bad!
how many feet in a yard?
In reply to cricketest
Depends on how many people. If there are two people and one is missing a leg, it might be 3.
you got me...
The opening question (no pun intended) describes how to make money from bitcoin.
Keep buying and selling the same asset over and over without market information.
In reply to Ayenmol Harharhar...very funny. Norm, here's something to keep U busy. It's probably, tea & water for U.
Use these clues to write the "mystery number."
The number has four digits.
The number is greater than 24, but less than 25.
The sum of the digits is 13.
A 6 is in the hundredths place.
In reply to openning
man, I am now seeing this post. how could this be a challenge for someone with a basic education???
@maj, Donald Trump understands you and has your soul kept safe and appreciates you... never you mind about the 3 attempts.
In reply to pelon
In reply to BeatDball
The number is greater than 24, but less than 25.
The sum of the digits is 13.
A 6 is in the hundredths place.
sum 13
2+4+x+6 = 13
x = 13 - (2+4+6)
x = unknown mystery of the universe
In reply to pelon NOT, unkil peelon! Homonyms my bwoy, homonyms! Figure it!? Nah gwine give U more hints.
In reply to cricketest
how big is the yard ?, and what if my yard bigger than yours ... I would be better able to fit more feet.
That Q is relative to what you determine yard to be.
I just facting around on a Friday!!
In reply to BeatDball
Nah gwine give U more hints.
Hints... bro your riddle was too easy.
Are you suggesting I gave you the wrong answer???? re-read my formula. it is clear as day. unless YOU can't do the maths
24.16
Mathematically I see no other outcome, but would be entertained by any answer you have.
we know 24.x6
I wrote the formula for x
if it is not x = 1 then you worded it wrong
24.16 is just too easy
In reply to pelon
How is the sum of 24.16 equal to 13?
Ok sum of digits....got it.
In reply to Ayenmol
Bless you
In reply to pelon
Was hasty on that response.
In reply to Ayenmol Wow! So, U are a badjohn, eh? Good for you sah!
In reply to BeatDball
Not sure what you mean...
In reply to Ayenmol You did it! U figured it! Well done.
Ah, come on, man! This stuff did not even keep amateurs like pelon and Ayenmol busy. Get real! Was its simplicity the "mystery"?
In reply to BeatDball
Boss... dat was too easy. You gave away 3 of 4 digits and said the 4 digits sum to 13.... i mean...
Here's a tea & water one for fun. A factory in New Guinea makes chopsticks. During a typical 12-hour day, 130,956 chopsticks are made. If the factory sells each chopstick for 3 cents, how many dollars' worth of chopstick does the factory produce in one hour?
In reply to BeatDball
Come on, man. Bring on the real stuff. This is the equivalent of a Bishoo long hop!
First off, a chopstick factory in New Guinea? I suppose those must be wooden chop sticks, made of some sort of resin-free wood.
Anyways,
Income per 12-hr day = 130956 x 3 / 100 = $3928.68
Income per hour = $3928.68 / 12 = $327.39.
In reply to Norm Used to be a Common Entrance teacha? U have a somewhat unusual way of doing the shoite. Btw, these are warming-up stuff.
In reply to BeatDball
Sort of.
So it seems - in everything.
Here we go Normy...In the Museum Theater, there are 75 rows of seats. The first 25 rows of the theater have 12 seats per row, and the rest of the theater has 14 seats per row. If rows 1 through 50 are reserved for school groups, how many people can sit in the reserved section? Ok, just till next weekend...here's one more: Mr Rivera goes on TV's Newsforum to be interviewed by 3 local journalists. The journalists' mean age is 42, their median age is 45, and the range of their ages is 23. What are their ages?
In reply to BeatDball
Thanks, bro. I see you have no faith in the others tho!
1. Total seats in reserved area
= 25 rows x 12 seats each + 25 rows x 14 seats each
= 300 + 350
= 650 seats
2. Let ages be a, b and c.
Total age = 3 x mean = 3 x 42 = 126
a + b + c = 126 (Equation 1)
b = 45 (median) (Equation 2)
a - c = 23 (range) (Equation 3)
Add (1) and (3)
(a + b + c) + (a - c) = 2a + b = 126 + 23 = 149
2a + b = 149 (Equation 4)
Substitute (2) into (4)
2a + b = 2a + 45 = 149
2a = 149 - 45 = 104
a = 52
From (3)
a - c = 23
52 - c = 23
52 - 23 = c
c = 29
a = 52, b = 45, c = 29
In reply to Norm Skites! U are wusser than badjohn bai...the algebraic solution to the second problem was second-to-none! Outstanding...I was expedient...I mentally figured that their total was 126...the median, 45, was given...so, the sum of the two unknowns is 126 - 45 = 81! Then by trial & error, I tried to get two number whose total was 81 & at the same time whose difference, the range, is 23! I knew there was an algebraic solution, but, I have to get away from U!!
Runs work in Zyger, which is 7,856 meters from his home. Runs' drive to work is 100 blocks long. 11 traffic lights are evenly spaced along the route, including one outside Runs' home and another by his office.
1. How far is the third traffic light from the fourth?
2. How long is an average block?
3. Runs' round trip takes 16 minutes 40 seconds. How fast, in meters per second, does he drive?
In reply to BeatDball
There are 10 intervals between the 11 lights, if there is one at the beginning and one at the ending. The lights are all the same distance apart. That distance is 7856/10 = 785.6 m.
The average block is 7856/100 = 78.56 m long.
The round trip length is 7856 x 2 = 15712 m.
Travel time is 16 min 40 sec = 16 x 60 + 40 = 1000 sec.
Speed = length / time = 15712 / 1000 = 15.712 m/s.
In reply to Norm Oh mih mummah! Normy...I gaan to cove & John!
Oh, M +*_%$#@+ C! I had part 1 wrong! I'm really going to Cove & John!
Get yer Exercise book Normy... The students learn that the zoo's three Alaskan bears have a combined weight of 3,000 pounds. The 'papa' bear weighs 300 more pounds that the 'mama' bear. The 'mama' bear weighs 4 times as much as the 'baby' bear. How much does each bear weigh?
Papa Bear weighs P lbs, Mama Bear M and Baby B.
M = 4B.
P = M + 300.
Total = P + M + B = 3000.
P + M + B = (M + 300) + M + B
=(4B + 300) + 4B + B
= 9B + 300 = 3000
9B = 3000 - 300 = 2700
B = 300, M = 1200, P = 1500
In reply to Norm
Answer this...
The Injection Problem:
In the environment of a shock, only particles with energies that exceed the thermal energy by much can cross the shock and 'enter the game' of acceleration. What mechanism causes the particles to initially have energies sufficiently high to do so?
In reply to DukeStreet Nah come show off here sah! A good fraction of us couldnt get close! Btw, that was a tea & water problem for Normy...but, here's something more challenging. Rita, Carlos, Felix and Molly passed out fliers for the club's film party. Rita passed out 1/4 of the fliers. Carlos passed out 1/2 of those left. Felix passed out 8 fliers and Molly passed out the remaining 4 fliers. How many fliers were there originally?
In reply to BeatDball
32?
rita 1/4
carlos 1/2 of whats left 3/4 ie 3/8
total so far is 5/8....remaining 3/8 = 12
1/8 = 4
4*8 = 32
In reply to DukeStreet
First order Fermi acceleration
In reply to Dan_De_Lyan Where's Norman? I ent playing wid U fellas!
In reply to DukeStreet
Is this a reading problem? Will a Wikipedia link do?
What mechanism? You mean what mathematical construct that approximates the acceleration of particles resulting from random distribution of energy discharged from a chemical, electrical or heat source?
In reply to BeatDball
These fellas trying to use big words on you. Ultimately, big words should be broken down to small words for general consumption. If one cannot reduce an apparently complex subject to simple language suitable for everyone, then one probably may not really understand the complex problem.
Answer to the latest problem.
Let the number of flyers be F.
Rita passes out 1/4 of them. So the remainder is 3/4F.
Carlos passes out a half of the remainder. So he passes out 1/2 of 3/4F = 3/8F.
Rita and Carlos passed out 1/4F + 3/8F = 2/8F + 3/8F = 5/8F. The remainder is now 3/8F.
Felix and Molly pass out the remainder = 8 + 4 = 12 flyers. Thus 3/8F = 12, and F = 8×12/3 = 32.
In reply to Norm Of course, if you were to explain this to a middle schooler, you would do this pedagogically!? More so, the 'bears' problem. Gwine tell you of how I did mine as soon as I'm thru feeding & walking my 7mo old, 60lbs pitbull puppy, Finn as in ragamuffin!
Here's how I would do the 'bears' problem with 6th or 7th graders... Let x = the weight of baby bear; then mama bear is 4 times that...= 4(x) lbs. Poupah bear, the big badjohn is 300 lbs more than mommy bear, so he will weigh = 4(x) + 300 lbs! The total weight of the three bears is 3000 lbs. So, to solve algebraically, x + 4x + 4x + 300 = 3000. Combine the 'Xs', we have 9x + 300 = 3000; bottomline we want x by itself; so, first we get rid of 300 by subtracting it from both sides of the equation to get 9x = 2700. Now, to get x by itself, we divide by 9 to both sides to get, x = 300! So, baby bear weighs 300 lbs; mommy bear is 4 times that, 4(300) = 1200 lbs and poupah bear, the big badjohn is 300 lbs more than mommy, 1200 + 300 = 1500 lbs! Of course, I would usually elicit as much from the class as possible...giving hints along the way.
As I said before, I'm not a math person...I just use a methodical approach...mental math is not for me! Guess what? When we were at the cemetery (burial ground for Leg 1 islanders), at my dad's funeral, 4 years ago...my then 8yo boy would look at headstones & within seconds he would tell you of how long the person lived!
In reply to BeatDball
An explanation must be designed for a specific audience. It must also consider which part of that audience it is targeting mostly. In the case of school kids, are you targeting all of them or only the smarter ones?
Anyway, you only know how well you yourself understand a subject until you have to teach it. Students could ask the most difficult questions!
In reply to Norm Bang on! I anticipated your comeback. I was unlike the teachers back home, who only targeted & reinforced the good ones.
Here's a warm-up:
1. We are a number of numbers. Each of us is 600, rounded to the nearest hundred. How many numbers are we?
2. We are many numbers, but when we are rounded to the nearest ten, we are always 450. What numbers are we?
3. To the nearest ten, we are 150, but to the nearest hundred, we are 200. What numbers are we?
In reply to BeatDball
Problem not clearly defined. Are the numbers integers? Does 5 get rounded up or down?
Assuming integers and that 5 is rounded up, answers are:
1. All integers from 550 to 649.
2. All integers from 445 to 454.
3. All integers from 150 to 154.
In reply to Norm Bai! Wtf! I'm getting the flick outta here!!!
Here's the warm-up: Dukes, a salesman for the Apex Shirt Company, is flying from New York to Denver on business. His plane takes off from New York at 7am Eastern time. If the flight takes 3.5 hours, at what time does the plane land in Denver? (Denver is on Mountain time, which is 2 hours earlier than Easter time.) Dont laff...as I said it's a warm-up.
In reply to BeatDball
Man, how much warm-ups are we going to do?
Mountain Time is 2 hours "earlier" than Eastern Time? Isn't that very misleading? It is more like "Mountain Time is 2 hours behind Eastern Time".
7 + 3.5 = 10:30 AM Eastern
10:30 AM Eastern = 08:30 AM Mountain.
Ok, ok badjohn, here's a harder one: There is a three hour time difference between Detroit & Los Angeles. (When it's 1 o'clock in Los Angeles, it is 4 o'clock in Detroit.) Bigzinc lives in Detroit. She called her grandfather in Los Angeles at 4:47 pm Detroit time. They talked for 28 minutes. Exactly at 3 hours 58 minutes later, Bigzinc's grandfather left for the supermarket. What time was it in Los Angeles when he went to the market?
In reply to BeatDball
Harder? Not really. Just more pieces, but the concept is the same.
Work in LA Time, because the answer is required in LA Time.
Called at 4:47 pm Detroit Time = 1:47 pm LA Time.
Talk for 28 minutes. Talk ended at 1:47 + :28 = 2:15 pm.
To supermarket 3 hrs 58 min later.
Left at 2:15 + 4:00 - :02 = 6:15 - :02 = 6:13 pm.
Left for supermarket at 6:13 pm LA Time.
In reply to Norm Very cute in borrowing 2 minutes to make computation easier, then giving it back! No worries mate, gine give you a hard one...later tho.
In reply to openning
Prove that 2^n x 3^2n - 1 is divisible by 17 for all positive integral values of n.
In reply to culpepperboy
Good one, culpepperboy!
First off, does the expression really produce 17?
Setting n = 1,
2^1 x 3^2 - 1 = 2 x 9 - 1 = 17! Wow.
OK, so if it is true for (n + 1) also, then it will be true for all positive integer values of n. The proof is demonstrated by substituting (n+1) for n in the original equation. If the resulting equation also produces multiples of 17 upon substitution of positive integers for n, then it will also do so for any other positive integer, since n is arbitrary.
So,
2^(n+1) = 2^n x 2^1 = 2 x 2^n.
3^(2 x (n+1)) = 3^(2n + 2) = 3^(2xn) x 3^2 = 9 x 3^(2xn),
and
2^(n+1) x 3^(2x(n+1)) - 1 = 2 x 2^n x 9 x 3^(2xn) - 1.
Again, setting n = 1
2 x 2^1 x 9 x 3^2 - 1 = 2 x 2 x 9 x 9 - 1
= 4 x 81 - 1 = 324 - 1 = 323.
323 / 17 = 19.
NB. I kept the solution to arithmetic, to avoid re-arranging somewhat lengthy equations obtained after substituting (n+1) for n in the original equation.
In reply to culpepperboy What is the limit of x over 1, as x approaches infinity? The limit of 1 over x, as x approaches infinity.
In reply to BeatDball
x/1 -> inf = inf
1/x -> inf = 0
This bowling is like the Bdesh bowling last night (1st T20I) ...!
In reply to Norm I'm outta here! Good night. But, be prepared...a hard hard one is on its way...soon.
In reply to BeatDball
Try capadulla, bro.
In reply to Norm At my age, I have to!
In reply to Norm
Incomplete proof
0/20. I mark hard
In reply to Norm
Alright then. Let's see your solution to the 3x+1 problem.
In reply to culpepperboy
Informal (maybe), but complete. It is sufficient to show that the equation based on (n+1) meets the requirements (multiple of 17) for the equation based on n. The formal proof would have you rearrange the equation resulting from (n+1) to show that it has the same form as the original equation.
What is the 3x + 1 problem?
In reply to Norm The jackrass trying to mek we a 'mocking stock!' My wife used that ole guyneez term on me...i wanted to die laffing since i didnt hear it for decades! Anyway, he's trying to tranquilize the fun we are having. That shoite he's giving us is an algebraic expression & not a mathematical sentence. You cannot do anything with it, except if he gives us value(s) of x....
In reply to BeatDball
google it then
In reply to Norm
Link Text
In reply to BeatDball
Take any natural number x. If x is even, divide it by 2 to get x/2, if x is odd multiply it by 3 and add 1 to obtain 3x+1. Repeat the process indefinitely. The conjecture is that no matter what number you start with, you will always eventually reach 1.
Prove it!!
In reply to Norm
3 students on spring break go into a hotel. The man behind the desk says a room is $30 so each student pays $10 and goes to the room.
A while later the man behind the desk realized the room was only $25 so he sent the bellboy to the 3 students' room with $5. On the way the bellboy couldn't figure out how to split $5 evenly between the 3 students, so he gave each student a $1 and kept the other $2 for himself.
This meant that the 3 students each paid $9 for the room, which is a total of $27 add the $2 that the bellboy kept = $29. Where is the other dollar?
In reply to culpepperboy Wtf? We are talking Middle School math!
In reply to culpepperboy
This "problem" is always flawed and...quite frankly...stupid...
Each student spent $9...totaling $27.00....Split between effective bill $25.00 and tip $2.00
Please don't waste our time again.
In reply to BeatDball
Nobody touch the 3x+1 problem so I had to come back to wunnuh level!!
In reply to culpepperboy Look dr smarty pants...i took 3 calculus classes & didnt get beyond Bs! I'm having fun with Normy - dont muck it up!
In reply to BeatDball
A part of math(s), nevertheless. Some of this "theoretical" stuff has led to important solutions for real life problems. Some countries pay a lot of attention to math theory, even in high school - more than the USA does.
In reply to culpepperboy
For example?
It seems to me that, as x tends to infinity, (3x + 1) will also tend to infinity, for real integers.
In reply to DAVE400
Man, you mark "mo harder" than Culpepperboy!
In reply to culpepperboy
Hahahaha! Alright, let's see your solution to the 3x + 1 problem, without plagiarizing via some link.
In reply to BeatDball
Not a problem, man. We will all learn something from the variety of problems and responses.
CXC Maths 1
Ad Maths A
Advnce Maths A
Advanced Futher Maths B (still hurt over that...limed too much in A levels)
In reply to Norm
I ask you to solve a problem and you asking for MY solution?
Just keep it simple algebra you can do in your head, no cheating:
6+4/2(1+2) = x
What is the value of x
In reply to Norm
Remember the rules, that only applies if the number is odd.
Give me a number and I will demonstrate.
In reply to pelon
What is this 2nd form math class?
In reply to culpepperboy
Just wait man, pemdas clears out the weeds
In reply to Norm
Here is an example: Let's say x is 197.
197 is odd, so multiply by 3 and add 1
592 is even so divide divide by 2
296 is even so divide divide by 2
148 is even so divide divide by 2
74 is even so divide divide by 2
37 is odd, so multiply by 3 and add 1
112 is even so divide divide by 2
56 is even so divide divide by 2
28 is even so divide divide by 2
14 is even so divide divide by 2
7 is odd, so multiply by 3 and add 1
22 is even so divide divide by 2
11 is odd, so multiply by 3 and add 1
34 is even so divide divide by 2
17 is odd, so multiply by 3 and add 1
52 is even so divide divide by 2
26 is even so divide divide by 2
13 is odd, so multiply by 3 and add 1
40 is even so divide divide by 2
20 is even so divide divide by 2
10 is even so divide divide by 2
5 is odd, so multiply by 3 and add 1
16 is even so divide divide by 2
8 is even so divide divide by 2
4 is even so divide divide by 2
2 is even so divide divide by 2
1
In reply to pelon 10 divided by 6; 10/6 = x? Wow! Daiz a hard one bai.
In reply to DAVE400 Stay away! This aint for U!
In reply to BeatDball
Recap: 6+4/2(1+2) = x
Your answer: 10/6 = x You are WRONG!
In reply to pelon
6+4/2(1+2) = x
10/2(3)=15
In reply to openning
6+6 = 12
x = 12
In reply to Kay
In reply to pelon x = 10/6 = 1 4/6 = 1 2/3 or 1.67 to the nearest hundredth! Gwallang.
In reply to openning
10/2(3)=15 WRONG
In reply to BeatDball
x = 10/6 = 1 4/6 = 1 2/3 or 1.67
Wrong!
In reply to culpepperboy
Thanks fo the example, culpepper. The problem statement is now clear.
The term x/2 has a smaller effect than the 3x term. Therefore, convergence will occur only if even values of x occur more frequently than odd values of x. The proof must hinge upon showing this. This is some sort of numbers theory problem, suitable for a "pure" mathematician.
I cannot solve this without researching it online. So, I give up!
In reply to pelon
Assuming the order of precedence is: (), * or /, and finally + or -, then left to right for operators at the same level:
If / = division operator only:
6+4/2(1+2) = 6+4/2*(1+2) = 6+4/2*3 = 6+2*3 = 6+6 = 12.
If / = division operator and vinculum (terms after / form a single group):
6+4/2(1+2) = 6+4/(2*(1+2)) = 6+4/(2*3) = 6+4/6 = 20/3.
The first solution (12) is a more literal interpretation of the problem.
In reply to Norm
Yes. 12 and only 12 is the answer.
In reply to pelon
Your problem is a test of knowledge...remembering the sequence of the operations...
Nothing more.
The order of operations doesnt apply here...how? Show me. U take the sum of the numerators and the sum of the product of the denominator & then simplify.
Pokey Pelon...try this: 6/2(1+2) = x.
In reply to BeatDball
9 times a day I want you to do some algebra..
9 times a day I want you to do some algebra.. and on the ninth time, remember that order of operations rules ALWAYS applies in algebra.
Do you still need me to actually answer your post?
In reply to pelon I know treeknees are badjohns when it comes to math...yea, show me!
In reply to BeatDball
The one you asked 6/2(1+2) = x
the answer is 9 no rocket science there. 6 divided 2 = 3
3 multiplied by 3 = 9 Very straight forward Form 1 stuff...
Now I took it one notch further (like Form 1 week 3)
6+4/2(1+2) = x
I intentionally made it so you had to KNOW order of operations.
Brackets
Orders (exponents)
Division
Multiplication
Addition
Subtraction
Follow the rules
Brackets First
we get 6+4/2*3
now Division and Multiplication
we get 6+(2*3)
now lastly the Addition
6+6
which all day every day equals 12
In reply to pelon PEMDAS prior to 1917 makes more sense. Get lost - dont come back!
In reply to BeatDball
lol...
Farmer Ridge has a problem. He is taking a fox, a chicken and a bag of corn to the market. His problem is that he has to cross a river, but his boat can hold only one of the three items at a time. If he leaves the fox and the chicken alone together, the fox will eat the chicken. If he leaves the chicken and the corn alone together, the chicken will eat the corn. How can Farmer Ridge take all three safely across the river?
Norm...Pelon...where are you blokes? Here's one to tickle alyuh: Cricketmygame enjoys hiking. He hikes at a rate of 4 miles per hour. He plans to to hike 24.5 miles on a forest trail. He wants to arrive at the trail's end in 5.5 hours. Will he make it if continues to hike at the same rate?
In reply to BeatDball
Something is wrong with you man.
They are 2 very simple ways to answer this most ridiculously simple query: NO!
needs to cover 24.5 miles moving at a FIXED rate of 4 mph (odd that it could be fixed, but ok)
NO, by division
24.5/4 = 6.125 or 6hrs 7mins
No, by multiplication
5.5*4 = 22 Miles
Either way, it is revealed by math an 8 year old could do. Go enjoy de season man.
In reply to pelon Jeez! That was meant to tickle ya! Shucks man...oh, what of the chicken, the fox & the corn?
In reply to pelon 6 hours 7 minutes & 30 seconds!
In reply to BeatDball
cool razz
1st carry chicken
2nd next carry fox (left back with corn), on the way back, carry chicken BACK (or he will be eaten)
3rd after putting chicken back, pack and carry corn over (otherwise chicken will eat it), then return to the (other side, where the fox is alone) with corn and drop it off.
4th return BACK and finally carry chicken
I see that as workable.
At no time is chicken with fox
or chicken with corn alone
In reply to pelon Time for me to be glued to my tv watching Forensic Files, cricket or Fox News!
In reply to BeatDball
1st round trip: Take chicken over, return empty.
2nd round trip: Take corn over, return with chicken.
3rd round trip: Take fox over, return empty.
4th trip: Take chicken over. No need to return.
In reply to BeatDball
Watching WI beat Bdesh, for a change!
Depends on where the lazy skunt is.
If he is at the beginning of the hiking trail then he will traverse only 4 (mph) x 5.5 (hrs) = 22 miles. So, no.
When will you take some capadulla and come up with a hard one, banna?
In reply to Norm I just have one driving lesson this AM. As soon as I get back, watch out! Gwine be a hard one...oh, a small cup of neem + karila tea every quarterly would suffice. My amerindian fren tries to goad me into trying this, try that...if i 'lash' once or twice a week (for my age), i am okay...but, not sure if aunty is happy!
Here back bench bwoys: Carl, Amy, Steven and Martha ran for class president. Martha received one more vote than Carl. Amy received twice as many votes as Steven. Steven received three more votes than Martha. Who won the election?
In reply to BeatDball
M = C + 1
A = 2 * S
S = M + 3
Four unknowns (A, C, M & S) and 3 equations. This requires a trial-and-error solution.
Set M = 1, results in:
C = M - 1 = 0, S = 4 and A = 8.
Thus, the order is: (A,S,M,C) = (8,4,1,0), and Amy won.
Is the above solution unique?
Set M = 2 results in:
C = 1, S = 5, and A = 10.
The solution is now: (A,S,M,C) = (10,5,2,1).
Thus, the solution set is infinite, but the order is unique.
Amy won.
In reply to Norm Your work & explanation is, bang on! Wheh u from sah? I want your village, town, city & country! Ok, here's one...tea & water. Sara White, Hillary Brown, and Steven Green were sitting reading the election results. Sara said, "Our shirts are the colors of our names, but none of us is wearing the color shirt that matches our name. Isnt that funny?" The student in the brown shirt said, "I dont think that's funny." What color was each student wearing? There's a particular problem...very hard...but, I, now cant locate the darn thing! I'll keep looking.
In reply to BeatDball
1. Sara White is not wearing a white or brown shirt. So Sara is wearing a green shirt.
2. Hillary Brown is not wearing a brown or green shirt. Hillary is wearing a white shirt.
3. Steven Green is not wearing a green or white shirt. Steven is wearing a brown shirt.
In reply to Norm You would be an outstanding Middle or High School mathematics teacher. I'm curious about your oratory or delivery...it was my strongest asset. I knew of this other math teacher (Ashkenazi jew & we know of their IQ - highest!)...sometimes I would have to consult him for assistance...he was a shabby dresser & his delivery was poor - he wasnt an effective teacher. Of course, if he had an orderly classroom...like one in suburbia & not in an inner city!
Still looking, but, here's one for you to mash-up! In the mayoral race, Dave Herbert ran against Judy Longstreet. The results of the election were 23,251 votes for Herbert, 23,828 votes for Longstreet and 9,539 votes for other candidates. What percent of the votes did each candidate receive? Who won? by what percent of the vote? One more as I cannot find that blinking problem...A rack of clothes at a factory holds 12 skirts and 8 blouses. Each skirt contains 5 feet of fabric. Each blouse contains 4 feet. How many yards of fabric were used to make the clothes? Just do it - no sarcasm! Close one & do it with your left hand, if you feel so unchallenged!
In reply to BeatDball
I was a middle school teacher for a few months in Guyana. I also taught Structures, Fluid Mechanics and Engineering Materials to university students for 5 years, in Guyana.
Ultimately, an engineer needs to have practical experience, which is why I have been a practicing civil engineer in California for over 25 years now and have not gone back to teaching.
Teaching can be a very fulfilling job tho!
In reply to Norm Hmmmm...outstanding! You are truly a badjohn. Btw, my uncle Teddy, mom's brother who left Guyana in the 50s for England is a retired engineer...Her Majesty's govt had called him back to work. He's presently in Guyana!
Here's a very challenging one before I go back to work tomorrow! A magnetic tape for one computer stores 31.5 characters per millimeter. The entire tape can store about 8,500,000 fewer characters than the number of characters per millimeter times 10 to the 6th power. About how many characters can the entire tape store? Normy, U pepperpot done?
In reply to BeatDball
Still have a few days worth in the pot. Will "yam it down" by the end of the week!
That tape can store 31.5 x 10^6 - 8,500,000
= 31.5 x 10^6 - 8.5 x 10^6
= (31.5 - 8.5) x 10^6
= 23 x 10^6
= 23 million characters.
In reply to Norm Same here...mine will finish by weekend. But, I have to go to Lil Guyana Bake shop to get more bread. Bought close to $20 worth of bread for the Pepperpot. Would you believe it, but my 12+yo boy also worked it out?!
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